How do you solve 14-x=3x-214x=3x2?

1 Answer
Jul 8, 2016

x = 4x=4

Explanation:

For problems like this you want to get the variable on one side of the equation and your constants ( a number on its own) on the other side.

Put your variables on the right side of the equation by adding x on both sides. You should end up with:

14 = 4x-214=4x2

Add 2 on both sides of the equation so the constants are on the left side leaving 4x on the right and 16 on the left:

16 = 4x16=4x

Divide both sides by 4 to solve for x:

16/(4) = (4x)/(4)164=4x4

x=4x=4