How do you divide #( x^3 + x^2 + 4x + 4 )/(x - 2 )#?

1 Answer
Tony B
Jul 9, 2016

#x^2+3x+10+24/(x-2)#

Explanation:

#color(white)(..)#

#" "x^3+x^2+4x+4#
#color(red)(+x^2)(x-2)->color(white)(.)ul(x^3-2x^2)" "larr" Subtract"#
#" "0color(white)(.)+3x^2+4x+4#
#color(red)(+3x)(x-2)->" "color(white)(.)ul(3x^2-6x)" "larr" Subtract"#
#" "0+10x+4#
#color(red)(+10)(x-2)->" "ul(10x-20)" "larr" Subtract"#
#" "color(red)(0+24" "larr" Remainder")#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#(x^3+x^2+4x+4) -:(x-2)" "color(red)(=" "x^2+3x+10+24/(x-2)#

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