If y varies inversely as x, and y = 12 as x = 2, how do you find y for the x-value of 6?

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Answer 1 · 2016-07-09T15:56:06

#x=4#

As #x# and #y# are inversely proportional, the equation can be represented as #x = k/y#.

Substituting #x=2# and #y=12#, we get #2 = k/12# => # k = 12*2# => #k=24#.

Equation can be represented as #x = 24/y#. So, when #y = 6#, we get #x = 24/6# => #x=4#

Answer 2 · 2016-07-09T15:57:12

#y = 4#

Write as an inverse proportion first then make an equation by multiplying by k,

#yprop1/x " " rArr " " y = k/x " " k = x xx y#

Find the value of k.

#k = 2 xx 12 = 24#

#y = 24/x " "rArr " "y = 24/6#

#y = 4#

You can now find any value of y or x if you are given the x or the y value.