How do you factor completely $2b^2-2b-12$ ?

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Answer 1 · 2016-07-10T01:19:59

$2(b-3)(b+2)$

First factorise by dividing everything by $2$ and putting a $2$ outside the brackets.
$2(b^2-b-6)$
Then factorise normally
$2(b-3)(b+2)$

How do you factor completely 2b^2-2b-122b^2-2b-12?