Question

How do you find the derivative of `x ln (x) - x`?

Answer 1

Knowing the product rule for derivatives, which tells us that

`d/dx[f(x)g(x)] = f(x)g'(x) + f'(x)g(x)`, we can let

`y= x ln(x) -x`, then

`y' = x(1/x) + 1(ln(x)) -1`

`=1 + ln(x) -1`

`=ln(x)`