Question

How many grams of oxygen are required to produce 55.6 g water vapor?

Answer 1

Approx. `50*g` dioxygen are necessary.

Explanation:

`H_2(g) + 1/2O_2(g) rarr H_2O(g)`

`"Moles of water"` `=` `(55.6*g)/(18.01*g*mol^-1)` `=` `3.09*mol`

If there are `3.09*mol` of water, then clearly, there were `1.54*mol` `O_2(g)` as a reactant.

And thus `"mass of oxygen"` `=` `1.54*molxx32.00*g*mol^-1`.