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Question #fa554

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Jul 12, 2016

$sin(pi/3+7/6pi)+ sin(pi/3)+ sin(7/6pi)$

$=sin(2/6pi+7/6pi)+ sin(pi/3)+ sin(pi+pi/6)$

$=sin(9/6pi)+ sin(pi/3)-sin(pi/6)$

$=sin(3/2pi)+ sin(pi/3)-sin(pi/6)$

$=sin(pi+pi/2)+ sin(pi/3)-sin(pi/6)$

$=-sin(pi/2)+ sin(pi/3)-sin(pi/6)$

$=-1+sqrt3/2-1/2$

$=-3/2+sqrt3/2$

$=1/2(sqrt3-3)$

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