How do you multiply (3y-y^2)/(y^3-27) div y/(y^2+3y+9)?

1 Answer
Jul 14, 2016

-1

Explanation:

=> (3y-y^2)/(y^3-27) * (y^2+3y+9)/y
=> (y(3-y))/(y^3-3^3) * (y^2+3y+9)/y

=>(cancel(y)(3-y))/(y^3-3^3) * (y^2+3y+9)/cancel(y)

[a^3-b^3 = (a-b) (a^2+b^2+ab)

=>(3-y)/[(y-3) (y^2+3y+9)] * (y^2+3y+9)
=>(3-y)/[(y-3) cancel(y^2+3y+9)] * cancel(y^2+3y+9)
=>(3-y)/[(y-3)
=>(3-y)/-(3-y)

=>1/-1
=> -1