How do you multiply (3y-y^2)/(y^3-27) div y/(y^2+3y+9)? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Dimri Jul 14, 2016 -1 Explanation: => (3y-y^2)/(y^3-27) * (y^2+3y+9)/y => (y(3-y))/(y^3-3^3) * (y^2+3y+9)/y =>(cancel(y)(3-y))/(y^3-3^3) * (y^2+3y+9)/cancel(y) [a^3-b^3 = (a-b) (a^2+b^2+ab) =>(3-y)/[(y-3) (y^2+3y+9)] * (y^2+3y+9) =>(3-y)/[(y-3) cancel(y^2+3y+9)] * cancel(y^2+3y+9) =>(3-y)/[(y-3) =>(3-y)/-(3-y) =>1/-1 => -1 Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify \frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} ? How do you divide and reduce the expression to the lowest terms 2xy \-: \frac{2x^2}{y}? How do you divide \frac{x^2-25}{x+3} \-: (x-5)? How do you divide \frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)? How do you simplify (w^2+6w+5)/(w+5)? How do you simplify (x^4-256)/(x-4)? See all questions in Division of Rational Expressions Impact of this question 1824 views around the world You can reuse this answer Creative Commons License