How do you convert #-6 - 6i sqrt 3# to polar form?
1 Answer
Jul 14, 2016
Explanation:
In polar form,
Comparing it with
we get
Squaring and adding 1 and 2,
Dividing equation 1 by 2
Real part of complex no =
Imaginary part of complex no =
At 3rd quadrant
Substituting the value in equation