How do you change #(1/5)^4 = 1/625# into log form?

1 Answer
Will
Jul 15, 2016

#4ln(5) = ln(625)#

Explanation:

if by log form you are referring to the natural logarithm then you apply the function as such

#ln((1/5)^4) = ln(1/625)#

#4ln(1/5) = ln(1/625)#

#4ln(1) - 4ln(5) = ln(1) -ln(625)#
technically the log of anything that is 1 is 0
#- 4ln(5) = -ln(625)#
#4ln(5) = ln(625)#

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