Question

How do you solve `ln(x+4)=ln7`?

Answer 1

Taking the `e`-xponential of both sides we get

`cancel(e)^(cancel(ln)(x+4)) = cancel(e)^(cancel(ln) 7)`

`x+4 = 7`

Subtracting `4` from both sides gives us our final answer of

`x = 3`