How do you convert #x = -3# to polar form?
1 Answer
Jul 19, 2016
Explanation:
Using the formula that converts
#"cartesian " hArr" polar"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta)color(white)(a/a)|)))# Substitute into equation
#rcostheta=-3rArrr=(-3)/costheta" in polar form"#