How do you find the vertex, focus and directrix of # x^2 + 6y = 0#?

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Answer 1 · 2016-07-19T11:14:09

Vertex is #(0,0)#

Focus is #(0,-3/2)#

Eqn. of Directrix is #y=3/2, i.e., 2y-3=0#

For the Parabola #x^2=4by#, Vertex is #(0,0)#, Focus is #(0,b)# and

eqn. of Directrix is #y=-b#.

Here, #4b=-6 rArr b=-3/2#

ence, the Vertex is #(0,0)#

Focus is #(0,-3/2)#

Eqn. of Directrix is #y=3/2, i.e., 2y-3=0#