Question

How do you factor the expression `-14x+8+6x^2`?

Answer 1

2(x - 1)(3x - 4)

Explanation:

Bring the expression to standard form:
`f(x) = 6x^2 - 14x + 8`
Since a + b + c = 0
- One real root is (1) and the factor is (x - 1)
- One real root is `(c/a = 8/6)` and the factor is `(x - 8/6)`
Factor form of f(x):
`f(x) = a(x - x1)(x - x2) = 6(x - 1)(x - 8/6) = (x - 1)(6x - 8) = 2(x - 1)(3x - 4)`