How do you solve #4y+13=37#?

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Answer 1 · 2016-07-20T03:36:47

#color(purple)("y=6")#

#color(indigo)("Subtract 13 on both sides:")#

#4y+cancel13=37#
#color(white)(aa) -cancel13 -13#

13 cancels out on the left side, and when you subtract 13 from 37 on the right side you obtain 24:

#4y=24#

#color(green)("Divide both sides 4 to get y by itself.")#

#(cancel"4"y)/cancel4=24/4#

Now you are just left with #y# on the left side and 6 on the right side.

Thus,
#color(red)"y=6"#