How do you solve #2^(3-x) = 565#?

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Answer 1 · 2016-07-21T14:29:23

#x=3-(log 565)/(log 2)=-6.142107057#

We start from the given equation

#2^(3-x)=565#

Take the logarithm of both sides

#log 2^(3-x)=log 565#

#(3-x)*log 2=log 565#

#3-x=log 565/log 2#

#3-log 565/log 2=x#

and

#x=3-(log 565)/(log 2)=-6.142107057#

God bless....I hope the explanation is useful