How do you factor #x - 6 = -x^2 #? Algebra Polynomials and Factoring Factoring Completely 1 Answer Deepak G. Jul 21, 2016 #x=-3# OR #x=2# Explanation: #x-6 =-x^2# OR #x^2+x-6=0# OR #x^2+3x-2x-6=0# OR #x(x+3)-2(x+3) =0# OR #(x+3)(x-2) = 0# so either #x+3 =0# #x=-3# OR #x-2=0# #x=2# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 983 views around the world You can reuse this answer Creative Commons License