How do you write the equation of the line with point (2, 1) with slope 3?

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Answer 1 · 2016-07-22T03:55:59

#y=3x-5#

Let #(x,y)# be a point on the line. Then the slope of the segment joining it to #(2,1)# (which, of course, is just the slope of our line) is

#{y-1}/{x-2}#

Thus we have

#{y-1}/{x-2} = 3#

This is the equation of the straight line that we want. Rearranging, we can write the equation in the standard form

#y-1 = 3(x-2)#
or
#y-1 = 3x-6#
or
#y=3x-5#