Question #60216

1 Answer
Jul 23, 2016

#256/625#

Explanation:

Let the# P (h,k)# is any point on the curve #4x^5=5y^4#

Hence this coordinate will satisfy the equation of the curve,
So we have

#4h^5=5k^4=>k^4/h^5=4/5.........(1)#

Now differentiating equation of the given curve w.r.to x we ge

#4*5x^4=5*4y^3(dy)/(dx)=>(dy)/(dx)=x^4/y^3#

If m is the slope of the tangent to the curve at #P(h,k)# then

#m=((dy)/(dx))_(h,k)=h^4/k^3#

Now

#"Length of subtangent at (h,k) "(T) =k/m=k^4/h^4#

#"Length of subnormal at (h,k) "(N) =k*m=h^4/k^2#

#"So the required ratio"=T^3/N^2=(k^4/h^4)^3/(h^4/k^2)^2=k^12/h^12*k^4/h^8#

#=k^16/h^20=(k^4/h^5)^4=(4/5)^4=256/625#

Inserting #k^4/h^5=4/5# from (1)