How do you solve #log_7(-2b+10)=log_7(3b)#?

Question

1809 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-23T08:08:26

#b=2#

The solution

#log_7 (-2b+10)=log_7 (3b)#

Take the anti-logarithm of both sides of the equation

#7^(log_7 (-2b+10))=7^(log_7 (3b))#

#-2b+10=3b#

Solving for b

#3b+2b=10#

#5b=10#

#(5b)/5=10/5#

#b=2#

God bless....I hope the explanation is useful.