What is the mass of #4.76*10^21# platinum atoms?

1 Answer
anor277
Jul 23, 2016

Well #6.0221xx10^(23)# platinum atoms have a mass of #195.08*g#, so you tell us.

Explanation:

So we simply take the quotient, and multiply this number by the mass of Avogadro's number of platinum atoms.

And thus,
#(4.76xx10^(21))/(6.0221xx10^(23))xx195.08*g=??g#

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