How do you find #(-3+7i)(1-2i)#?
1 Answer
Jul 25, 2016
11 + 13i
Explanation:
Expand the brackets using ,for example, the FOIL method.
#(-3+7i)(1-2i)=-3+6i+7i-14i^2#
#=-3+13i-14i^2#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#-3+13i-14i^2=-3+13i+14=11+13i#
#rArr(3+7i)(1-2i)=11+13i#
