How do you simplify #4(5a - 3)#?
1 Answer
Jul 25, 2016
20a - 12
Explanation:
Use the
# color(blue)"distributive law"# which means multiply each term inside the bracket by the 4 outside.
#rArrcolor(red)(4)(5a-3)=(color(red)(4)xx5a)+(color(red)(4)xx(-3))=20a-12#
#rArr4(5a-3)=20a-12#