How do you find the slope and intercept of $2 x - 5 y = - 10$ $2x-5y= -10$ ?

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How do you find the slope and intercept of $2 x - 5 y = - 10$ $2x-5y= -10$ ?

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Answer 1 · 2016-07-25T15:07:29

$x$ $x$ -intercept is $x = - 5$ $x=-5$

$y$ $y$ -intercept is $y = 2$ $y=2$

slope= $\frac{2}{5}$ $2/5$

Explanation:

$2 x - 5 y = - 10$ $2x-5y=-10$
$x$ $x$ -intercept is when $y = 0$ $y=0$
So by putting $y = 0$ $y=0$ in the above equation we get
$2 x - 5 (0) = - 10$ $2x-5(0)=-10$
or
$2 x - 0 = - 10$ $2x-0=-10$
or
$2 x = - 10$ $2x=-10$
or
$x = - \frac{10}{2}$ $x=-10/2$
or
$x = - 5$ $x=-5$ --------------Ans $1$ $1$

$y$ $y$ -intercept is when $x = 0$ $x=0$
So by putting $x = 0$ $x=0$ in the equation $2 x - 5 y = - 10$ $2x-5y=-10$ we get
$2 (0) - 5 y = - 10$ $2(0)-5y=-10$
or
$0 - 5 y = - 10$ $0-5y=-10$
or
$- 5 y = - 10$ $-5y=-10$
or
$5 y = 10$ $5y=10$
or
$y = \frac{10}{5}$ $y=10/5$
$y = 2$ $y=2$ --------------Ans $2$ $2$

In the equation $y = m x + c; m$ $y=mx+c; m$ is the slope
So we can rewrite equation $2 x - 5 y = - 10$ $2x-5y=-10$
as
$5 y = 2 x + 10$ $5y=2x+10$
or
$y = (\frac{2}{5}) x + \frac{10}{5}$ $y=(2/5)x+10/5$
or
$y = (\frac{2}{5}) x + 2$ $y=(2/5)x+2$

Hence slope= $\frac{2}{5}$ $2/5$ ----------Ans $3$ $3$

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How do you find the slope and intercept of $2 x - 5 y = - 10$ $2x-5y= -10$ ?

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Science

Math

Humanities

... and beyond

How do you find the slope and intercept of 2x−5y=−102x-5y= -10?

1 Answer

Explanation:

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Impact of this question

How do you find the slope and intercept of $2 x - 5 y = - 10$ $2x-5y= -10$ ?