How do you find the sum of the unit vectors (2,2,7) and (5, -6, 2)?

1 Answer
Jul 26, 2016

Since the given #(2,2,7)# and #(5,-6,2)# are not unit vectors it is not clear what was intended by this question.

Explanation:

Possibility 1: Sum of the unit vectors with the same orientation as the given values
Since #sqrt(2^2+2^2+7^2)=sqrt(57)#
the unit vector corresponding to #(2,2,7)# is
#color(white)("XXX")(2/sqrt(57),2/sqrt(57),7/sqrt(57))#

Similarly the unit vector corresponding to #(5,-6,2)# is
#color(white)("XXX")(5/sqrt(65),-6/sqrt(65),2/sqrt(65))#

The sum of these unit vectors is
#color(white)("XXX")(2/sqrt(57)+5/sqrt(65),2/sqrt(57)-6/sqrt(65),7/sqrt(57)+2/sqrt(165))#
(these terms could be evaluated but given the question's ambiguity I have not bothered with the effort involved)

Possibility 2: Unit vector with the same orientation as the sum of the given vectors
#(2,2,7)+(5,-6,2)=(7,-4,9)#
with corresponding unit vector:
#color(white)("XXX")(7/sqrt(146),-4/sqrt(146),9/sqrt(146))#