How do you solve 4^(-3x)=0.25? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Gerardina C. Jul 26, 2016 x=1/3 Explanation: Since 0.25=1/4=4^-1 you can write the equivalent equation: 4^(-3x)=4^-1 then -3x=-1 (cancel(-3)x)/cancel(-3)=-1/-3 x=1/3 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 5032 views around the world You can reuse this answer Creative Commons License