How do you solve $4^(-3x)=0.25$ ?

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Answer 1 · 2016-07-26T21:31:22

$x=1/3$

Since $0.25=1/4=4^-1$

you can write the equivalent equation:

$4^(-3x)=4^-1$

then

$-3x=-1$

$(cancel(-3)x)/cancel(-3)=-1/-3$

$x=1/3$

How do you solve 4^(-3x)=0.254^(-3x)=0.25?