Question

What is the perimeter of a triangle with corners at `(8 ,5 )`, `(9 ,1 )`, and `(3 ,4 )`?

Answer 1

Perimeter is `15.930`

Explanation:

As perimeter is sum of all the sides, let us find all the sides of triangle formed by `(8,5)`, `(9,1)` and `(3,4)`. This will be surely distance between pair of points, (which is given by `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`. Hence the three sides are:

`a=sqrt((9-8)^2+(1-5)^2)=sqrt(1+16)=sqrt17=4.123`

`b=sqrt((3-9)^2+(4-1)^2)=sqrt(36+9)=sqrt45=6.708` and

`c=sqrt((3-8)^2+(4-5)^2)=sqrt(25+1)=sqrt26=5.099`

Hence perimeter is `4.123+6.708+5.099=15.930`