What is the perimeter of a triangle with corners at (8 ,5 ), (9 ,1 ), and (3 ,4 )?

1 Answer
Jul 27, 2016

Perimeter is 15.930

Explanation:

As perimeter is sum of all the sides, let us find all the sides of triangle formed by (8,5), (9,1) and (3,4). This will be surely distance between pair of points, (which is given by sqrt((x_2-x_1)^2+(y_2-y_1)^2). Hence the three sides are:

a=sqrt((9-8)^2+(1-5)^2)=sqrt(1+16)=sqrt17=4.123

b=sqrt((3-9)^2+(4-1)^2)=sqrt(36+9)=sqrt45=6.708 and

c=sqrt((3-8)^2+(4-5)^2)=sqrt(25+1)=sqrt26=5.099

Hence perimeter is 4.123+6.708+5.099=15.930