Question

How do you find the antiderivative of `(cosx)^2`?

Answer 1

`intcos^2xdx=x/2+(sin2x)/4+c`

Explanation:

To find antiderivative i.e. integral of `cos^2x`, we can use formula `cos^2x=1/2(1+cos2x)`

`intcos^2xdx=int[1/2(1+cos2x)]dx`

= `int(1/2+(cos2x)/2)dx`

= `1/2[x+(sin2x)/2]+c`

= `x/2+(sin2x)/4+c`