How do you find the midpoint of the line segment joining A(-1,3) and B(-5,9)?

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Answer 1 · 2016-07-27T11:24:34

#(-3,6)#

It is the mean values

#=>P_("mid")->(x,y)=( (-1-5)/2,(3+9)/2) = (-3,6)#

Answer 2 · 2016-07-27T11:27:47

#(-3,6)#.

The midpoint #M(x,y)# of the segment joining pts. #(x_1,y_1) and (x_2,y_2)# is given by #x=(x_1+x_2)/2, y=(y_1+y_2)/2#.

Hence, the reqd. mid-pt. is #(-3,6)#.

Answer 3 · 2016-07-27T11:27:55

#M(-3, 6)#

In easy English this is:

"Average of the x-values and the average of the y-values."

The formula is #M((x_1 + x_2)/2; (y_1+ y_2)/2)#

#M((-1-5)/2; (3+9)/2)#

#M((-6)/2; 12/2)#

=#M(-3, 6)#