How do you simplify #sqrt7/root5(7)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Deepak G. Jul 28, 2016 #=root10(7^3# Explanation: #sqrt7/root5(7)# #=7^(1/2)/(7^(1/5))# #=7^((1/2-1/5))# #=7^((5-2)/10# #=7^(3/10)# #=root10(7^3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1019 views around the world You can reuse this answer Creative Commons License