How do you simplify #16 ÷ 4 times 2 - 7# using PEMDAS?

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Answer 1 · 2016-07-29T14:02:07

Corrected answer

#" "16-:4xx2-7" " =" " 1#

Using strict application of process

P#-># Parenthesise (brackets)
E #-># Exponents (powers)
M #-># Multiply
D #-># Divide
A #-># Add
S #-># Subtract

I am advised that it is better to write this as

P-E-MD-AS as multiply and divide have the same priority. As do add and subtract.

Given:#" "16-:4xx2-7#

So reading left to right

#=>[(16-:4)xx2]-7#

#=>[4xx2]-7#

#=>8-7 = 1#