How do you find the asymptotes for #(x^2 - 5x + 6)/(x - 3)#?
1 Answer
Jul 29, 2016
This function has no asymptotes. It has a hole at
Explanation:
#(x^2-5x+6)/(x-3)=(color(red)(cancel(color(black)((x-3))))(x-2))/color(red)(cancel(color(black)((x-3))))=x-2#
with exclusion
This is a straight line with a hole at
It has no asymptotes.
