If an object is moving at #11 m/s# over a surface with a kinetic friction coefficient of #u_k=22 /g#, how far will the object continue to move?

1 Answer
P dilip_k
Jul 30, 2016

Considering the conservation of mechanical energy we can say that KE of the moving body is equal to the work done by it against the force of kinetic friction.If m represents mass and v the velocity of the moving object then

#mu_kmgxxd=1/2mxxv^2# ,where d is the distance traversed.

#=>d=v^2/(2mu_kg)=11^2/(2*22/g*g)=11/4=2.75m#

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