Question

How do you find the domain and range of `(2/3)^x – 9`?

Answer 1

Domain: `(-oo, +oo)`
Range: `(-9, +oo)`

Explanation:

For the domain:
x can take any value. Therefore
Domain: `(-oo, +oo)`

The horizontal asymptote of the graph is `y=-9`, therefore it does not include the value `y=9`. It is the approached value of the function as x approaches `+oo`

Range: `(-9, +oo)`

Kindly see the graph for visual aid.

God bless....I hope the explanation is useful.