How do you solve #y = 2x – 4# and #7x – 5y = 14# using substitution?

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Answer 1 · 2016-07-31T06:00:50

#x=2; y=0#

Since #y=2x-4#, let's substitute the expression #2x-4# in y in the second equation:

#7x-5(2x-4)=14#

#7x-10x+20=14#

#-3x=14-20#

#-3x=-6#

#x=2#

Now let's substitute the value 2 in x in the first equation:

#y=2(2)-4=0#