Vertex at# (-3/2,-29/4)#. Axis of symmetry is#x= -3/2#
Explanation:
#y=x^2+3x-5 = (x+3/2)^2-9/4-5=(x+3/2)^2-29/4:.#Comparing with general vertex form of equation #y=a(x-h)^2+k# we get vertex at #(h,k) or (-3/2,-29/4)#.Axis of symmetry is #x= -3/2# graph{x^2+3x-5 [-20, 20, -10, 10]} [Ans]