How do you solve #5x^2+25x=0#?

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Answer 1 · 2016-07-31T18:44:47

# x=0, or, x=-5#.

#5x^2+25x=0 rArr 5x(x+5)=0 rArrx=0, or, x+5=0#

# rArr x=0, or, x=-5#

Answer 2 · 2016-07-31T18:45:27

x = 0 , x = -5

Begin by factorising the left side.

#color(red)(5x)(x+5)=0#

#rArr 5x=0rArrx=0" or " x+5=0rArrx=-5#

Thus solution is x = 0 , x = -5