How do you factor completely #3x^3 + 24x^2 + 48x#?

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Answer 1 · 2016-07-31T20:29:25

#=3x(x+4)^2#

#3x^3+24x^2+48x#
#=3x(x^2+8x+16)#
#=3x(x^2+2x(4)+4^2)#
#=3x(x+4)^2#

Answer 2 · 2016-07-31T20:30:04

=#3x(x + 4)(x+4)#

Take out a common factor first. In this case #3x#

#3x^3 + 24x^2+ 48x#

=#3x(x^2 + 8x+ 16)#

=#3x(x + 4)(x+4)#