Question

If `3 L` of a gas at room temperature exerts a pressure of `15 kPa` on its container, what pressure will the gas exert if the container's volume changes to `5 L`?

Answer 1

The gas will exert a pressure of `9 kPa`

Explanation:

Let's begin by identifying our known and unknown variables.

The first volume we have is `3 L` , the first pressure is `15kPa` and the second volume is `5 L`. Our only unknown is the second pressure.

The answer can be determined by using Boyle's Law:

Rearrange the equation to solve for the final pressure by dividing both sides by `V_2` to get `P_2` by itself like this:

`P_2=(P_1xxV_1)/V_2`

Plug in your given values to obtain the final pressure:

`P_2=(15\kPa xx 3\ cancel"L")/(5\cancel"L")` = `9kPa`