Question

How do you solve `ln(n^2+12)=ln(-9n-2)`?

Answer 1

`n=-7` or `n=-2`

Explanation:

raising the equation to `e` we can drop the `log` so

`n^2+12 = -9n-2`

`n^2+9n-14=0`

`(n+2)(n+7)=0`

`n=-7` or `n=-2` are potential candidates.

#now you plug in and make sure
and it turns out that they both work