How do you graph the line 4x+3y-12=0?

1 Answer
Aug 4, 2016

y intercept of the function is present at the point: (0,4)
and x intercept of the function is present at the point: (3,0)
See full explanation for more detail:

Explanation:

In order to clearly recognise the x and y intercepts of the function we may convert the given function to linear gradient form. That being:
y=mx+c
Where:

c is the constant determining the y intercept.
and m is the gradient of the function.

Therefore, let us do this:
->3y=-4x+12
Dividing both sides by 3, we get:
y=-4/3x+4

This implies that the y intercept of the function is 4.
We can prove this via the statement:
y intercepts where x=0:
Therefore:
y=0*x+4
This implies that the y intercept of the function is present at the point: (0,4)

We can thus determine the x intercept using the statement:
x intercepts where y=0:
->0=-4/3x+3
:.4/3x=4
x=3
This implies that the x intercept of the function is present at the point: (3,0)

If we plot these points on a Cartesian plane and draw a line between the two, the graph has been drawn.

Attached below is a graph of the function with the intercepts in frame:

graph{y=-4/3x+4 [-9.54, 10.46, -2.92, 7.08]}