How do you find the derivative of #f(x) = (x-1)(x^2+2)^3#?
1 Answer
Aug 6, 2016
#dy/dx=(x^2+2)^3[(6x^2-6x)+1]#
Explanation:
Given -
#y=(x-1)(x^2+2)^3#
#dy/dx=[(x-1)3(x^2+2)^2(2x)]+[(x^2+2)^3 (1)]#
#dy/dx=[6x^2-6x)(x^2+2)^3]+[(x^2+2)^3]#
#dy/dx=(x^2+2)^3[(6x^2-6x)+1]#
