How do you write the equation of an ellipse with vertices at (-5,1) and (-1,1) and co-vertices at (-3,2) and (-3,0)?

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Answer 1 · 2016-08-06T15:18:38

#(x+3)^2/4 +(y-1)^2/1=1#

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Center (h,k) lies on the x-axis .

so midpoint of vertices is the center.

#(h,k) =((-5+(-1))/2,(1+1)/2)=(-3,1)#

a=length of semi-major axis #a=2#
b=length of semi-minor axis#b =1#

Equation of ellipse:

#(x-h)/a^2+(y-k)/b^2=1#

Plug the values of a,b and (h,k)

#(x+3)^2/4 +(y-1)^2/1=1#