Question

How do you factor `3x^2 - 27(2-x)^2`?

Answer 1

`=-12(x-3)(2x-3)`

Explanation:

`3x^2-27(2-x)^2`
`=3x^2-27(4+x^2-4x)`
`=3x^2-27(4)-27x^2+27(4x)`
`=3x^2-108-27x^2+108x`
`=-24x^2+108x-108`
`=-12(2x^2-9x+9)`
`=-12(2x^2-6x-3x+9)`
`=-12(2x(x-3)-3(x-3))`
`=-12(x-3)(2x-3)`