Question

How do you do titration problems to find molarity?

Answer 1

See below.

Explanation:

Titration is used to determine the unknown molarity (`M`) of a solution (called analyte) using a titrant, which is a solution of known concentration.

Considering the analyte is an acidic solution (unknown molarity) and that it will be titrated using a basic solution with a known molarity (assuming monoprotic acid and base).

At the equivalence point, the number of mole of `H^+` ions will be equal to the number of mole of `OH^-` ions:

`n_(H^+)=n_(OH^-)`

Note that the relationship between molarity and number of mole is:

`M=n/V` where `V` is the volume of the solution.

Thus, `n=MxxV`.

Therefore, `M_(a)xxV_(a)=M_(b)xxV_(b)`

`=>M_(a)=(M_(b)xxV_(b))/(V_(a))`

Here is a video that fully explains this topic:
Lab Demonstration | Acid - Base Titration.