Question

How do you solve for `x` in `(x+a)m=y`?

Answer 1

`x=y/m-a`

Explanation:

`(x+a)m = y`
Expand: `xm+am=y`

Subtract `am` from both sides:

`xm+am-am=y-am->xm=y-am`
Divide through by `m: ->` `x=y/m-(acancelm)/cancelm`

`x=y/m-a`