How do you solve #4=4(k+3)# using the distributive property?
1 Answer
Aug 11, 2016
k = - 2
Explanation:
The distributive property means multiplying the terms inside the bracket by 4.
#rArr4=color(red)(4)(k+3)=4k+12# we now have to solve 4k+ 12 = 4
subtract 12 from both sides of the equation.
#rArr4k+12cancel(-12)=4-12# That is : 4k = - 8
divide both sides by 4.
#rArr(cancel(4)^1 k)/cancel(4)^1=cancel(-8)^(-2)/cancel(4)^1rArrk=-2#
