Question #516aa

1 Answer
Aug 11, 2016

C_M=0.301(mol)/L

Explanation:

The molarity (C_M) is calculated by:

C_M=n/V

where, n is the number of mole of the solute (NaOH) and
V is the volume of the solution.

To find the number of mole of NaOH we can use the following relationship:

n=m/(MM)

where, m is the mass of NaOH and MM is the molar mass of NaOH: MM=40.0g/(mol)

=>n=m/(MM)=(29.5cancel(g))/(40.0cancel(g)/(mol))=0.738mol

The molarity is then can be found as:

C_M=n/V= (0.738mol)/(2.45L)=0.301(mol)/L ("corrected to 3 significant figures")