Question

Question #516aa

Answer 1

`C_M=0.301(mol)/L`

Explanation:

The molarity (`C_M`) is calculated by:

`C_M=n/V`

where, `n` is the number of mole of the solute (`NaOH`) and
`V` is the volume of the solution.

To find the number of mole of `NaOH` we can use the following relationship:

`n=m/(MM)`

where, `m` is the mass of `NaOH` and `MM` is the molar mass of `NaOH`: `MM=40.0g/(mol)`

`=>n=m/(MM)=(29.5cancel(g))/(40.0cancel(g)/(mol))=0.738mol`

The molarity is then can be found as:

`C_M=n/V= (0.738mol)/(2.45L)=0.301(mol)/L ("corrected to 3 significant figures")`