Question

What is the net area between `f(x) = cosx` and the x-axis over `x in [0, 3pi ]`?

Answer 1

`0`

Explanation:

This is expressed as:

`A=int_0^(3pi)cos(x)dx`

The antiderivative of `cos(x)` is `sin(x)`:

`A=[sin(x)]_0^(3pi)=sin(3pi)-sin(0)=sin(pi)-sin(0)=0`