How do you multiply #(x+2)(7x+8)#?

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Answer 1 · 2016-08-12T02:45:44

#7x^2+22x+16#

You simply expand the brackets like this:
#x*7x+x*8+2*7x+2*8#
Which gives the answer of:
#7x^2+22x+16#

Answer 2 · 2016-08-12T02:47:14

Expand the parentheses to get 4 terms

Expand the brackets to get #7x^2+14x+8x+16# = #7x^2+22x+16#